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4-2.Quadratic Equations and Inequations
medium
समीकरण $2{x^2} + 3x - 9 \le 0$ का हल होगा
A
$\frac{3}{2} \le x \le 3$
B
$ - 3 \le x \le \frac{3}{2}$
C
$ - 3 \le x \le 3$
D
$\frac{3}{2} \le x \le 2$
Solution
(b) $2{x^2} + 3x – 9 \le 0$
==> $2{x^2} + 6x – 3x – 9 \le 0$
==> $2x(x + 3) – 3(x + 3) \le 0$
==> $(2x – 3)(x + 3) \le 0$
==> $ – 3 \le x \le 3/2$.
Standard 11
Mathematics