Gujarati
4-2.Quadratic Equations and Inequations
medium

समीकरण $2{x^2} + 3x - 9 \le 0$ का हल होगा

A

$\frac{3}{2} \le x \le 3$

B

$ - 3 \le x \le \frac{3}{2}$

C

$ - 3 \le x \le 3$

D

$\frac{3}{2} \le x \le 2$

Solution

(b) $2{x^2} + 3x – 9 \le 0$

==> $2{x^2} + 6x – 3x – 9 \le 0$

==> $2x(x + 3) – 3(x + 3) \le 0$

==> $(2x – 3)(x + 3) \le 0$

==> $ – 3 \le x \le 3/2$.

 

Standard 11
Mathematics

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