The statement (mathrm{p} wedge(mathrm{p} righ | vedclass

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Question

$(\mathrm{p} \wedge(\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{q} \rightarrow \mathrm{r})) \rightarrow \mathrm{r}$

$\equiv(\mathrm{p} \wedge

Vedclass · Accepted Answer

a tautology

Vedclass · Answer

$(\mathrm{p} \wedge(\mathrm{p} ightarrow \mathrm{q}) \wedge(\mathrm{q} ightarrow \mathrm{r})) ightarrow \mathrm{r}$

$\equiv(\mathrm{p} \wedge(\sim \mathrm{p} \vee \mathrm{q}) \vee(\sim \mathrm{q} \vee \mathrm{r})) ightarrow \mathrm{r}$

$\equiv((\mathrm{p} \wedge \mathrm{q}) \wedge(\sim \mathrm{p} \vee \mathrm{r})) ightarrow \mathrm{r}$

$\equiv(\mathrm{p} \wedge \mathrm{q} \wedge \mathrm{r}) ightarrow \mathrm{r}$

$\equiv \sim(\mathrm{p} \wedge \mathrm{q} \wedge \mathrm{r}) \vee \mathrm{r}$

$\equiv(\sim \mathrm{p}) \vee(\sim \mathrm{q}) \vee(\sim \mathrm{r}) \vee \mathrm{r}$

$\Rightarrow 	ext { tautology }$

The statement $(\mathrm{p} \wedge(\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{q} \rightarrow \mathrm{r})) \rightarrow \mathrm{r}$ is :

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