The sum of integers from $1$ to $100$ that are divisible by $2$ or $5$ is
$3000$
$3050$
$4050$
None of these
Find the sum of integers from $1$ to $100$ that are divisible by $2$ or $5.$
If the first, second and last terms of an $A.P.$ be $a,\;b,\;2a$ respectively, then its sum will be
The sum of the numbers between $100$ and $1000$, which is divisible by $9$ will be
The number of common terms in the progressions $4,9,14,19, \ldots \ldots$, up to $25^{\text {th }}$ term and $3,6,9,12$, up to $37^{\text {th }}$ term is :
The solution of ${\log _{\sqrt 3 }}x + {\log _{\sqrt[4]{3}}}x + {\log _{\sqrt[6]{3}}}x + ......... + {\log _{\sqrt[{16}]{3}}}x = 36$ is