The sum of the first five terms of the series $3 + 4\frac{1}{2} + 6\frac{3}{4} + ......$ will be

  • A

    $39\frac{9}{{16}}$

  • B

    $18\frac{3}{{16}}$

  • C

    $39\frac{7}{{16}}$

  • D

    $13\frac{9}{{16}}$

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