System of equations x + y + z = 6 , x + 2y + 3z = 10,x + 2y + λ z = μ , has no solution for

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3 and 4 .Determinants and Matrices

hard

The system of equations $x + y + z = 6$, $x + 2y + 3z = 10,x + 2y + \lambda z = \mu $, has no solution for

A

$\lambda \ne 3,\mu = 10$

B

$\lambda = 3,\mu \ne 10$

C

$\lambda \ne 3,\mu \ne 10$

D

None of these

Solution

(b) The value of the determinant will vanish if $\lambda = 3$ and ${\Delta _1} \ne 0$, $\therefore \,\,\mu \ne 10$.

Standard 12

Mathematics

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