7.Binomial Theorem
easy

The term independent of $x$ in the expansion of ${\left( {{x^2} - \frac{1}{x}} \right)^9}$ is

A

$1$

B

$-1$

C

$-48$

D

None of these

Solution

(d) $(9 -r) (2) + r (-1) = 0$

==> $18 -2r -r = 0$ ==> $r = 6$

Thus term independent of $x$ is $^9{C_6}{(1)^3}{( – 1)^6} = 84.$

Standard 11
Mathematics

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