Time period of a mass suspended from a spring is T . If spring is cut into four equal parts and same

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13.Oscillations

easy

The time period of a mass suspended from a spring is $T$. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be

$T$

$\frac{T}{2}$

$2 T$

$\frac{T}{4}$

(AIPMT-2003)

Solution

(b)By cutting spring in four equal parts force constant (K) of each parts becomes four times so by using $T = 2\pi \sqrt {\frac{m}{K}} ;$ time period will be half i.e. $T' = T/2$

Standard 11

Physics

Two pendulums have time periods $T$ and $\frac{{5T}}{4}.$They start $S.H.M.$ at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has complete one oscillation ….. $^o$

easy

If a body of mass $0.98\, kg$ is made to oscillate on a spring of force constant $4.84\, N/m$, the angular frequency of the body is ….. $ rad/s$

easy

A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is $2.0 \mathrm{~N} \mathrm{~m}^{-1}$ and the mass of the block is $2.0 \mathrm{~kg}$. Ignore the mass of the spring. Initially the spring is in an unstretched condition. Another block of mass $1.0 \mathrm{~kg}$ moving with a speed of $2.0 \mathrm{~m} \mathrm{~s}^{-1}$ collides elastically with the first block. The collision is such that the $2.0 \mathrm{~kg}$ block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is. . . .
(image)

normal

(IIT-2018)

A mass $M$ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes $S.H.M.$ of time period $T$. If the mass is increased by m, the time period becomes $5T/3$. Then the ratio of $m/M$ is

medium

(AIIMS-2016)

A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)

medium

(NEET-2021)

The time period of a mass suspended from a spring is $T$. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be

Solution

Similar Questions

Two pendulums have time periods $T$ and $\frac{{5T}}{4}.$They start $S.H.M.$ at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has complete one oscillation ….. $^o$

If a body of mass $0.98\, kg$ is made to oscillate on a spring of force constant $4.84\, N/m$, the angular frequency of the body is ….. $ rad/s$

A mass $M$ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes $S.H.M.$ of time period $T$. If the mass is increased by m, the time period becomes $5T/3$. Then the ratio of $m/M$ is

A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)

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