The trajectory of projectile, projected from the ground is given by $y=x-\frac{x^2}{20}$. Where $x$ and $y$ are measured in meter. The maximum height attained by the projectile will be $...........\,m$

  • [JEE MAIN 2023]
  • A

    $5$

  • B

    $10 \sqrt{2}$

  • C

    $200$

  • D

    $10$

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