- Home
- Standard 12
- Mathematics
3 and 4 .Determinants and Matrices
medium
$\lambda$ અને $\mu$ ની કિમંત મેળવો કે જેથી સમીકરણ સંહતિ $x+y+z=6,3 x+5 y+5 z=26, x+2 y+\lambda z=\mu$ નો ઉકેલગણ ખાલીગણ થાય.
A
$\lambda=3, \mu \neq 10$
B
$\lambda \neq 2, \mu=10$
C
$\lambda=3, \mu=5$
D
$\lambda=2, \mu \neq 10$
(JEE MAIN-2021)
Solution
$D=\left|\begin{array}{lll}1 & 1 & 1 \\ 3 & 5 & 5 \\ 1 & 2 & \lambda\end{array}\right|=0$
$(5 \lambda-10)-1(3 \lambda-5)+(6-5)=0$
$2 \lambda-10+5+1=0$
$\lambda=2$ only one option satisfy
Atleast one If $\mathrm{D}_{1}, \mathrm{D}_{2}, \mathrm{D}_{3} \neq 0$
Standard 12
Mathematics
