The value of $\sum \limits_{n=0}^{1947} \frac{1}{2^n+\sqrt{2^{1994}}}$ is equal to

  • [KVPY 2014]
  • A

    $\frac{487}{\sqrt{2^{1945}}}$

  • B

    $\frac{1946}{\sqrt{2^{1947}}}$

  • C

    $\frac{1947}{\sqrt{2^{1947}}}$

  • D

    $\frac{1948}{\sqrt{2^{1947}}}$

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