The value of tan 7frac{1}{2}^circ is equal t | vedclass

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(b) We have $	an A = \frac{{\sin A}}{{\cos A}} $

$= \frac{{2\sin A\cos A}}{{2{{\cos }^2}A}} = \frac{{\sin 2A}}{{1 + {{\cos }^2}A}}$

Putting $A

Vedclass · Accepted Answer

$\sqrt 6  - \sqrt 3  + \sqrt 2  - 2$

Vedclass · Answer

(b) We have $	an A = \frac{{\sin A}}{{\cos A}} $

$= \frac{{2\sin A\cos A}}{{2{{\cos }^2}A}} = \frac{{\sin 2A}}{{1 + {{\cos }^2}A}}$

Putting $A = 7{\frac{1}{2}^o} $

$\Rightarrow 	an 7{\frac{1}{2}^o} = \frac{{\sin {{15}^o}}}{{1 + \cos {{15}^o}}}$ 

On simplification, we get $	an 7{\frac{1}{2}^o} = \sqrt 6 - \sqrt 3 + \sqrt 2 - 2$.

The value of $\tan 7\frac{1}{2}^\circ $ is equal to

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