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3.Trigonometrical Ratios, Functions and Identities
normal
$\sum_{r-1}^{18} cos^2(5r)^o,$ =
A
$\frac{19}{2}$
B
$\frac{7}{2}$
C
$\frac{17}{2}$
D
$0$
Solution
$=\cos ^{2} 5^{\circ}+\cos ^{2} 10^{\circ}+\ldots+\cos ^{2} 85^{\circ}+\cos ^{2} 90^{\circ}$
$=8+\frac{1}{2}=\frac{17}{2}$
Standard 11
Mathematics