The value of $tan^{-1} (\frac{sin2 -1}{cos2})$ is equal to:-

  • A

    $\frac{\pi}{2} - 1$

  • B

    $2 - \frac{\pi}{2}$

  • C

    $1- \frac{\pi}{4}$

  • D

    $ \frac{\pi}{4}-1$

Similar Questions

$\tan \alpha + 2\tan 2\alpha + 4\tan 4\alpha + 8\cot \,8\alpha = $

  • [IIT 1988]

${\sin ^4}\frac{\pi }{8} + {\sin ^4}\frac{{3\pi }}{8} + {\sin ^4}\frac{{5\pi }}{8} + {\sin ^4}\frac{{7\pi }}{8} = $

$(\sec 2A + 1){\sec ^2}A = $

The expression $\frac{{\cos 6x + 6\cos 4x + 15\cos 2x + 10}}{{\cos 5x + 5\cos 3x + 10\cos x}}$ is equal to

If $\cos \left( {\alpha + \beta } \right) = \frac{4}{5}$ and $\sin \left( {\alpha - \beta } \right) = \frac{5}{{13}}$,where $0 \le \alpha ,\beta \le \frac{\pi }{4}$ . Then $\tan 2\alpha =$ 

  • [AIEEE 2010]