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1. Electric Charges and Fields
medium
Three charges are placed at the vertices of an equilateral triangle of side ‘$a$’ as shown in the following figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $BC$ is
A
${Q^2}/(4\pi {\varepsilon _0}{a^2})$
B
$ - {Q^2}/(4\pi {\varepsilon _0}{a^2})$
C
Zero
D
${Q^2}/(2\pi {\varepsilon _0}{a^2})$
(AIIMS-2003)
Solution
(c) $|\overrightarrow {{F_B}} |\, = \,\,|\overrightarrow {{F_C}} | = k.\frac{{{Q^2}}}{{{a^2}}}$
Hence force experienced by the charge at $A$ in the direction normal to $BC$ is zero.
Standard 12
Physics
