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14.Probability
easy
ત્રણ સિક્કા એક વાર ઉછાળવામાં આવે છે. નીચે આપેલ ઘટનાની સંભાવના શોધો.
એક પણ કાંટો નહિ.
Option A
Option B
Option C
Option D
Solution
When three coins are tossed once, the sample space is given by $S =\{ HHH , HHT , HTH , THH , HTT , THT , TTH , TTT \}$
$\therefore$ Accordingly, $n ( S )=8$
It is known that the probability of an event $A$ is given by
$P ( A )=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n( A )}{n( S )}$
Let $I$ be the event of the occurrence of no tail.
Accordingly, $I$ $=\{ HHH \}$
$\therefore P(I)=\frac{n(I)}{n(S)}=\frac{1}{8}$
Standard 11
Mathematics
