Three numbers are in A.P. whose sum is 33 and | vedclass

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Question

(a) Suppose that three numbers are $a + d,\;a,\;a - d,$

therefore $a + d + a + a - d = 33$

$ \Rightarrow $$a = 11$

$a(a + d)(a - d) = 792$

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(a) Suppose that three numbers are $a + d,\;a,\;a - d,$

therefore $a + d + a + a - d = 33$

$ \Rightarrow $$a = 11$

$a(a + d)(a - d) = 792$

$ \Rightarrow $$11(121 - {d^2}) = 792$

$ \Rightarrow $$d = 7$

Then required numbers are $4, 11, 18.$

Hence smallest number is $4.$

Three numbers are in $A.P.$ whose sum is $33$ and product is $792$, then the smallest number from these numbers is

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