1. Electric Charges and Fields
medium

Three point charges of magnitude $5 \mu C , 0.16 \mu C$ and $0.3 \mu C$ are located at the vertices $A , B , C$ of a right angled triangle whose sides are $AB =3\,cm$, $BC =3 \sqrt{2}\,cm$ and $CA =3\,cm$ and point $A$ is the right angle corner. Charge at point $A$ experiences

$N$ of electrostatic force due to the other two charges.

A

$177$

B

$12$

C

$17$

D

$29$

(JEE MAIN-2022)

Solution

$F _{1}=\frac{ k \times 5 \times 0.3 \times 10^{-12}}{9 \times 10^{-4}}$

$=\frac{9 \times 10^{9} \times 5 \times 0.3 \times 10^{-12}}{9 \times 10^{-4}}$

$=1.5 \times 10=15\,N$

$F _{2}=\frac{9 \times 10^{9} \times 5 \times 0.16 \times 10^{-12}}{9 \times 10^{-4}}=8\,N$

force experienced by charge at $A =\sqrt{ F _{1}^{2}+ F _{2}^{2}}$

$=\sqrt{15^{2}+8^{2}}$

$=\sqrt{289}=17\,N$

Standard 12
Physics

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