Two bar magnets with magnetic moments $ 2 M $ and $M$ are fastened together at right angles to each other at their centres to form a crossed system, which can rotate freely about a vertical axis through the centre. The crossed system sets in earth’s magnetic field with magnet having magnetic moment $2M $ making and angle $ \theta $ with the magnetic meridian such that
$\theta = {\tan ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)$
$\theta = {\tan ^{ - 1}}\left( {\sqrt 3 } \right)$
$\theta = {\tan ^{ - 1}}\left( {\frac{1}{2}} \right)$
$\theta = {\tan ^{ - 1}}\left( {\frac{3}{4}} \right)$
A short magnet is allowed to fall along the axis of a horizontal metallic ring. Starting from rest, the distance fallen by the magnet in one second may be.....$m$
Two lines of force due to a bar magnet
A bar magnet of length $'l'$ and magnetic dipole moment $'M'$ is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be
Two equal bar magnets are kept as shown in the figure. The direction of resultant magnetic field, indicated by arrow head at the point $P$ is (approximately)
The diagram shows magnetic field lines. We move from above to below and back.Below shows the graph of variaton of magnetic flux with time. We will measure the flux of