Two blocks A and B of masses 1, kg and 2, kg are connected together by a spring and are r

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5.Work, Energy, Power and Collision

normal

Two blocks $A$ and $B$ of masses $1\, kg$ and $2\, kg$ are connected together by a spring and are resting on a horizontal surface. The blocks are pulled apart so as to strech the spring and then released. The ratio of $K.E.s$ of both the blocks is

$1$

$2$

$0.5$

$0.25$

Solution

From consv. of momentum. $\mathrm{p}_{1}=\mathrm{p}_{2}$ and

$\mathrm{KE}=\frac{\mathrm{p}^{2}}{2 \mathrm{m}}$

$\frac{\mathrm{KE}_{1}}{\mathrm{KE}_{2}}=\frac{\mathrm{p}_{1}^{2}}{\mathrm{p}_{2}^{2}} \times \frac{\mathrm{m}_{2}}{\mathrm{m}_{1}}=1 \times \frac{2}{1}=2$

Standard 11

Physics

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Two blocks $A$ and $B$ of masses $1\, kg$ and $2\, kg$ are connected together by a spring and are resting on a horizontal surface. The blocks are pulled apart so as to strech the spring and then released. The ratio of $K.E.s$ of both the blocks is

Solution

Similar Questions

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