Two boys are standing at the ends $A$ and $B$ of a ground where $AB = a$. The boy at $B$ starts running in a direction perpendicular to $AB$ with velocity ${v_1}.$ The boy at $A$ starts running simultaneously with velocity $v$ and catches the other boy in a time $t$, where $t$ is

  • [AIPMT 2005]
  • A

    $a/\sqrt {{v^2} + v_1^2} $

  • B

    $\sqrt {{a^2}/({v^2} - v_1^2)} $

  • C

    $a/(v - {v_1})$

  • D

    $a/(v + {v_1})$

Similar Questions

Which is the direction of instantaneous velocity for angular path ?

It takes one minute for a passenger standing on an escalator to reach the top. If the escalator does not move it takes him $3$ minute to walk up . ....... $\sec$ long will it take for the passenger to arrive at the top if he walks up the moving escalator ?

The figure shows the velocity $(v)$ of a particle plotted against time $(t)$

Figure shows a body of mass m moving with a uniform speed $v$ along a circle of radius $r$. The change in velocity in going from $A$ to $B$ is

Give explanation of position and displacement vectors for particle moving in a plane by giving suitable equations.