Two dice are thrown together. If numbers appearing on two dice are different, then probability that

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14.Probability

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Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is $6$

A

$\frac{5}{{36}}$

B

$\frac{1}{6}$

C

$\frac{2}{{15}}$

D

None of these

Solution

(c) Obviously numbers will be $\left( {\begin{array}{*{20}{c}}{\rm{I}}&{{\rm{II}}}\\{5,}&1\\{4,}&2\\{2,}&4\\{1,}&5\end{array}} \right)$.

Hence required probability $ = \frac{4}{{6\,\,.\,\,5}} = \frac{2}{{15}}$.

Standard 11

Mathematics

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