Two forces, each of magnitude F have a result | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $R = \sqrt {{A^2} + {B^2} + 2AB\cos 	heta } $

By substituting, $A = F,\;B = F$ and $R = F$ we get

$\cos 	heta = -\frac{1}{2}	herefore 	h

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(b) $R = \sqrt {{A^2} + {B^2} + 2AB\cos 	heta } $

By substituting, $A = F,\;B = F$ and $R = F$ we get

$\cos 	heta = -\frac{1}{2}	herefore 	heta = 120^\circ $

Two forces, each of magnitude $F$ have a resultant of the same magnitude $F$. The angle between the two forces is....... $^o$

Similar Questions

A particle is simultaneously acted by two forces equal to $4\, N$ and $3 \,N$. The net force on the particle is

The resultant force of $5 \,N$ and $10 \,N$ can not be ........ $N$

Two forces of magnitude $8 \,N$ and $15 \,N$ respectively act at a point. If the resultant force is $17 \,N$, the angle between the forces has to be .......

The resultant of $\vec A$ and $\vec B$ makes an angle $\alpha $ with $\vec A$ and $\beta $ with $\vec B$,

For the resultant of the two vectors to be maximum, what must be the angle between them....... $^o$