Two forces, each of magnitude F have a result | vedclass

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Question

(b) $R = \sqrt {{A^2} + {B^2} + 2AB\cos 	heta } $

By substituting, $A = F,\;B = F$ and $R = F$ we get

$\cos 	heta = -\frac{1}{2}	herefore 	h

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(b) $R = \sqrt {{A^2} + {B^2} + 2AB\cos 	heta } $

By substituting, $A = F,\;B = F$ and $R = F$ we get

$\cos 	heta = -\frac{1}{2}	herefore 	heta = 120^\circ $

Two forces, each of magnitude $F$ have a resultant of the same magnitude $F$. The angle between the two forces is....... $^o$

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