Two identical bodies are made of a material f | vedclass

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Question

(b)

Let specific heats of body at $100^{\circ} C$ is $S_1$ and that of body at $0^{\circ} C$ is $S_2$.

Let $T=$ common steady state temperature,

Vedclass · Accepted Answer

more than $50^{\circ} C$

Vedclass · Answer

(b)

Let specific heats of body at $100^{\circ} C$ is $S_1$ and that of body at $0^{\circ} C$ is $S_2$.

Let $T=$ common steady state temperature, then as the bodies are kept in contact.

Heat lost $=$ Heat gained

$m S_1(100-T)=m S_2(T-0)$

$\Rightarrow 100 S_1=T\left(S_1+S_2\right)$

$\Rightarrow T=\frac{100 \cdot S_1}{S_1+S_2}$

If $S_1=S_2$, then $T=50^{\circ} C$.

But given $S_1 > S_2$ and $S_1=S_2$

Under these conditions,

$\frac{S_1}{S_1+S_2} > \frac{1}{2}$

So, $T$ is more than $50^{\circ} C$.

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