14.Probability
easy

Two numbers are selected randomly from the set $S = \{ 1,\,2,\,3,\,4,\,5,\,6\} $ without replacement one by one. The probability that minimum of the two numbers is less than $4$ is

A

$\frac{1}{{15}}$

B

$\frac{{14}}{{15}}$

C

$\frac{1}{5}$

D

$\frac{4}{5}$

(IIT-2003)

Solution

(d) Total ways $= 2\,! \,^6{C_2} = 30$

Favourable cases $ = 30 – 6 = 24$

$\therefore$ Required probability $ = \frac{{24}}{{30}} = \frac{4}{5}$.

Standard 11
Mathematics

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