Two particles A and B of equal masses are suspended from two massless springs of spring constants K

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13.Oscillations

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Two particles $A$ and $B$ of equal masses are suspended from two massless springs of spring constants $K _{1}$ and $K _{2}$ respectively.If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is

A

$\frac{ K _{2}}{ K _{1}}$

B

$\frac{ K _{1}}{ K _{2}}$

C

$\sqrt{\frac{ K _{1}}{ K _{2}}}$

D

$\sqrt{\frac{ K _{2}}{ K _{1}}}$

(JEE MAIN-2021)

Solution

$A _{1} \omega_{1}= A _{2} \omega_{2}$

$A_{1} \sqrt{\frac{k_{1}}{m}}=A_{2} \sqrt{\frac{k_{2}}{m}}$

$\frac{ A _{1}}{ A _{2}}=\sqrt{\frac{ k _{2}}{ k _{1}}}$

Standard 11

Physics

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