Two point charges Q and -3Q are placed at som | vedclass

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Question

(b) The field produced by charge $-3Q$ at $A$, this is $E$ as mentioned in the Example.
$	herefore $ $E = \frac{{3Q}}{{{x^2}}}$ (along $AB$ directed

Vedclass · Accepted Answer

$-E/3$

Vedclass · Answer

(b) The field produced by charge $-3Q$ at $A$, this is $E$ as mentioned in the Example.
$	herefore $ $E = \frac{{3Q}}{{{x^2}}}$ (along $AB$ directed towards negative charge)
Now field at location of $-3Q$ i.e. field at $B$ due to charge $Q$ will be $E' = \frac{Q}{{{x^2}}} = \frac{E}{3}$ (along $AB$ directed away from positive charge)

Two point charges $Q$ and $-3Q$ are placed at some distance apart. If the electric field at the location of $Q$ is $E$ then at the locality of $ - 3Q$, it is

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