Two spherical bodies of mass M and 5M and rad | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

As the spherical bodies have their own size so the distance covered by both the body $12 \mathrm{R}-3 \mathrm{R}=9 \mathrm{R},$ but individual distanc

Vedclass · Accepted Answer

$7.5\, R$

Vedclass · Answer

As the spherical bodies have their own size so the distance covered by both the body $12 \mathrm{R}-3 \mathrm{R}=9 \mathrm{R},$ but individual distance covered by each body depends upon their masses.

We know that bodies are moving under the effect of mutual attraction only, so their position of centre of mass remains unaffected.

Let smaller body cover distance $x$ just before coll ision From $\mathrm{m}_{1} \mathrm{r}_{1}=\mathrm{m}_{2} \mathrm{r}_{2},$ we get

$\Rightarrow M x=5 M(9 R-x) \Rightarrow x=7.5 R$

Two spherical bodies of mass $M$ and $5M$ and radii $R$ and $2R$ respectively are released in free space with initial separation between their centres equal to $12\,R$. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is

Similar Questions

A particle of mass $M$ is at a distance $'a'$ from surface of a thin spherical shell of uniform equal mass and having radius $a$

Suppose the earth stopped rotating. Then, the weight a body will

In a satellite if the time of revolution is $T$, then $P E$ is proportional to ..........

The potential energy of a satellite of mass $m$ and revolving at a height $R_e$ above the surface of earth where $R_e =$ radius of earth, is

A body tied to a string of length $L$ is revolved in a vertical circle with minimum velocity, when the body reaches the upper most point the string breaks and the body moves under the influence of the gravitational field of earth along a parabolic path. The horizontal range $AC$ of the body will be