6.System of Particles and Rotational Motion
hard

Two uniform circular discs are rotating independently in the same direction around their common axis passing through their centres. The moment of inertia and angular velocity of the first disc are $0.1 \;kg - m ^{2}$ and $10\; rad \,s^{-1}$ respectively while those for the second one are $0.2 \;kg - m ^{2}$ and $5\; rad \,s ^{-1}$ respectively. At some instant they get stuck together and start rotating as a single system about their common axis with some angular speed. The Kinetic energy of the combined system is ...........$J$

A

$3.33$

B

$0.67$

C

$1.67$

D

$6.67$

(JEE MAIN-2020)

Solution

Both discs are rotating in same sense

Angular momentum conserved for the system

i.e. $\quad L _{1}+ L _{2}= L _{\text {final }}$

$I _{1} \omega_{1}+ I _{2} \omega_{2}=\left( I _{1}+ I _{2}\right) \omega_{ f }$

$0.1 \times 10+0.2 \times 5=(0.1+0.2) \times \omega_{f}$

$\omega_{ f }=\frac{20}{3}$

Kinetic energy of combined disc system

$\Rightarrow \frac{1}{2}\left( I _{1}+ I _{2}\right) \omega_{ f }^{2}$

$=\frac{1}{2}(0.1+0.2) \cdot\left(\frac{20}{3}\right)^{2}$

$=\frac{0.3}{2} \times \frac{400}{9}=\frac{120}{18}=\frac{20}{3} J$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.