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Question

$(b)$ $A H _{2}$ molecule in a nanotube is bound only by adhesive forces. So, its energy is least.

A hydrogen atom in a $H _{2}$ molecule is bound

Vedclass · Accepted Answer

$IV < II < I < III$

Vedclass · Answer

$(b)$ $A H _{2}$ molecule in a nanotube is bound only by adhesive forces. So, its energy is least.

A hydrogen atom in a $H _{2}$ molecule is bound by interatomic forces. So, its energy is less than the energy of an electron in $H _{2}$ molecule.

Proton in a carbon nucleus is bound because of strong nuclear forces. So, its energy is largest.

$	herefore$ Correct order is $IV < II < I < Ill$.

Using the Heisenberg uncertainty principle, arrange the following particles in the order of increasing lowest energy possible.

$(I)$ An electron in $H _{2}$ molecule

$(II)$ A hydrogen atom in a $H _{2}$ molecule

$(III)$ A proton in the carbon nucleus

$(IV)$ $A H _{2}$ molecule within a nanotube

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