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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$0.01 \,M$ ग्लायसीन विलयन की $pH$ क्या है ? $298 $ पर, ग्लायसीन के लिए $K{a_1} = 4.5 \times {10^{ - 3}}$ और $K{a_2} = 1.7 \times {10^{ - 10}}$ हैं
A
$3$
B
$10$
C
$6.1$
D
$7.2$
(AIIMS-2004)
Solution
(c) $K = K{a_1} \times K{a_2}$$ = 4.5 \times {10^{ – 3}} \times 1.7 \times {10^{10}}$
${H^ + } = \sqrt {Kc} $ $ = \sqrt {4.5 \times {{10}^{ – 3}} \times 1.7 \times {{10}^{ – 10}} \times .01} $
$ =0.87 \times {10^{ – 7}}$$pH = – \log \;0.87 \times {10^{ – 7}}$$ = 7 – 0.93 = 6.1$.
Standard 11
Chemistry
