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13.Nuclei
medium
What is the half-life (in years) period of a radioactive material if its activity drops to $1 / 16^{\text {th }}$ of its initial value of $30$ years?
A
$9.5$
B
$8.5$
C
$7.5$
D
$10.5$
(JEE MAIN-2022)
Solution
$A=A_{0} e^{-\lambda t}$
$-\lambda t =\ln \left(\frac{ A }{ A _{0}}\right)$
$-\frac{\ln 2}{ t _{1 / 2}} \times 30=\ln \left(\frac{1}{16}\right)$
$-\frac{\ln 2}{t_{1 / 2}} \times 30=-4 \ln 2$
$t _{1 / 2}=\frac{30}{4}=7.5\,yrs$
Standard 12
Physics