What is the half-life (in years) period of a | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$A=A_{0} e^{-\lambda t}$

$-\lambda t =\ln \left(\frac{ A }{ A _{0}}ight)$

$-\frac{\ln 2}{ t _{1 / 2}} 	imes 30=\ln \left(\frac{1}{16}ight)$

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

$A=A_{0} e^{-\lambda t}$

$-\lambda t =\ln \left(\frac{ A }{ A _{0}}ight)$

$-\frac{\ln 2}{ t _{1 / 2}} 	imes 30=\ln \left(\frac{1}{16}ight)$

$-\frac{\ln 2}{t_{1 / 2}} 	imes 30=-4 \ln 2$

$t _{1 / 2}=\frac{30}{4}=7.5\,yrs$

What is the half-life (in years) period of a radioactive material if its activity drops to $1 / 16^{\text {th }}$ of its initial value of $30$ years?

Similar Questions

In a mean life of a radioactive sample

Which of the following Statements is correct?

Radioactivity is

The activity of a sample is $64 × 10^{-5}\, Ci.$ Its half-life is $3\, days$. The activity will become $5 × 10^{-6}\, Ci$ after .........$days$

A radioactive sample of $U^{238}$ decay to $Pb$ through a process for which half life is $4.5 × 10^9$ years. The ratio of number of nuclei of $Pb$ to $U^{238}$ after a time of $1.5 ×10^9$ years (given $2^{1/3} = 1.26$)