Length of a simple pendulum, which ticks seconds?

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13.Oscillations

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What is the length of a simple pendulum, which ticks seconds?

Option A

Option B

Option C

Option D

Solution

the time period of a simple pendulum is given by,

$T=2 \pi \sqrt{\frac{L}{g}}$

From this relation one gets,

$L=\frac{g T^{2}}{4 \pi^{2}}$

The time period of a simple pendulum, which ticks seconds, is $2\, s$. Therefore, for $g=9.8 \,m s ^{-2}$ and $T=2 s , L$ is

$=\frac{9.8\left( m s ^{-2}\right) \times 4\left( s ^{2}\right)}{4 \pi^{2}}$

$=1 \,m$

Standard 11

Physics

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