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4-1.Newton's Laws of Motion
medium
નીચે આપેલી બળની જોડ સમતુલનમાં છે.
A
${F_1} = 3N,\,\,{F_2} = 5N,\,\,{F_3} = 9N$
B
${F_1} = 3N,\,\,{F_2} = 5N,\,\,{F_3} = 1N$
C
${F_1} = 3N,\,{F_2} = 5N,\,{F_3} = 15N$
D
${F_1} = 3N,\,\,{F_2} = 5N,\,\,{F_3} = 6N$
Solution
(d) Range of resultant of ${F_1}$ and ${F_2}$ varies between $(3+5)=8N$ and $(5 – 3) = 2N$.
It means for some value of angle $(\theta )$, resultant $6$ can be obtained.
So, the resultant of $3\,N$, $5\,N$ and $6\,N$ may be zero and the forces may be in equilibrium.
Standard 11
Physics
