- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
medium
Which pair do not have equal dimensions?
AForce and impulse
BAngular momentum and Planck constant
CEnergy and torque
DElastic modulus and pressure.
(AIPMT-2000)
Solution
$\text { For (A): }\text { Energy }= kg \cdot m ^2 \cdot s ^2=\left[ ML ^2 T ^{-2}\right]$
$\text { Torque }= kg \cdot m ^2 \cdot s ^2=\left[ ML ^2 T ^{-2}\right]$
$\text { For (B) : }\text { Force }= kg \times m / s ^2=\left[ MLT ^{-2}\right]$
$\text { Impulse }= kgm / s =\left[ MLT ^{-1}\right]$
$\text { For (C) : }\text { Angular momentum }= kgm ^2 / s =\left[ ML ^2 T ^{-1}\right]$
$\text { Planck's constant }= kgm ^2 / s =\left[ ML ^2 T ^{-1}\right]$
$\text { For (D) : }\text { Elastic modulus }= kg / m ^2=\left[ ML ^{-2}\right]$
$\text { Pressure }= kg / m ^2=\left[ ML ^{-2}\right]$
From the above data, only Force and Impulse does not have equal dimensions.
$\text { Torque }= kg \cdot m ^2 \cdot s ^2=\left[ ML ^2 T ^{-2}\right]$
$\text { For (B) : }\text { Force }= kg \times m / s ^2=\left[ MLT ^{-2}\right]$
$\text { Impulse }= kgm / s =\left[ MLT ^{-1}\right]$
$\text { For (C) : }\text { Angular momentum }= kgm ^2 / s =\left[ ML ^2 T ^{-1}\right]$
$\text { Planck's constant }= kgm ^2 / s =\left[ ML ^2 T ^{-1}\right]$
$\text { For (D) : }\text { Elastic modulus }= kg / m ^2=\left[ ML ^{-2}\right]$
$\text { Pressure }= kg / m ^2=\left[ ML ^{-2}\right]$
From the above data, only Force and Impulse does not have equal dimensions.
Standard 11
Physics
