3 and 4 .Determinants and Matrices
medium

વિસ્તરણ કર્યા સિવાય સાબિત કરો : $\Delta=\left|\begin{array}{ccc}x+y & y+z & z+x \\ z & x & y \\ 1 & 1 & 1\end{array}\right|=0$

Option A
Option B
Option C
Option D

Solution

 Applying $\mathrm{R}_{1} \rightarrow \mathrm{R}_{1}+\mathrm{R}_{2}$ to $\Delta,$ we get

$\Delta=\left|\begin{array}{ccc}
x+y+z & x+y+z & x+y+z \\
z & x & y \\
1 & 1 & 1
\end{array}\right|$

since the elements of $R_{1}$ and $R_{3}$ are proportional, $\Delta=0$

Standard 12
Mathematics

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