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1.Units, Dimensions and Measurement
medium
$P = \frac{{a - {t^2}}}{{bx}}$ છે જ્યાં $P$ દબાણ, $x$ અંતર અને $t$ સમય છે તો $a/b$ નું પરિમાણિક સૂત્ર શું થાય?
A
${M^{ - 1}}{L^0}{T^{ - 2}}$
B
${M^1}{L^0}{T^{ - 2}}$
C
${M^1}{L^0}{T^{ 2}}$
D
${M^1}{L^1}{T^{ - 2}}$
Solution
$P=\frac{a-t^{2}}{b x}$
$P=\left[M L^{-1} T^{-2}\right]$
$a$ will have same unit as $t^{2} .$ So, $a=\left[T^{2}\right]$
$b=\left[\frac{a-t^{2}}{p x}\right]=\frac{\left[T^{2}\right]}{\left[M L^{-1} T^{-2} L\right]}=\left[M^{-1} L^{0} T^{4}\right]$
$\frac{a}{b}=\frac{\left[T^{2}\right]}{\left[M^{-1} L^{0} T^{4}\right]}=\left[M L^{0} T^{-2}\right]$
Standard 11
Physics
