1.Units, Dimensions and Measurement
medium

समीकरण $P = \frac{{a - {t^2}}}{{bx}}$ में $P$ दाब, $x$ दूरी तथा $t$ समय है तब $\frac{a}{b}$ की विमा होगी

A

${M^{ - 1}}{L^0}{T^{ - 2}}$

B

${M^1}{L^0}{T^{ - 2}}$

C

${M^1}{L^0}{T^{ 2}}$

D

${M^1}{L^1}{T^{ - 2}}$

Solution

$[a] = [{T^2}]$ तथा $[b] = \frac{{[a – {t^2}]}}{{[P]\;[x]}} = \frac{{{T^2}}}{{[M{L^{ – 1}}{T^{ – 2}}]\,[L]}}$

==> $[b] = [{M^{ – 1}}{T^4}]$

अत:$\left[ {\frac{a}{b}} \right] = \frac{{[{T^2}]}}{{[{M^{ – 1}}{T^4}]}} = [M{T^{ – 2}}]$

Standard 11
Physics

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