- Home
- Standard 11
- Mathematics
14.Probability
medium
$4$ cards are drawn from a well-shuffled deck of $52$ cards. What is the probability of obtaining $3$ diamonds and one spade?
A
$ \frac{{^{13}{C_3}{ \times ^{13}}{C_1}}}{{^5{C_4}}}$
B
$ \frac{{^{13}{C_3}{ \times ^{13}}{C_1}}}{{^5{C_4}}}$
C
$ \frac{{^{13}{C_3}{ \times ^{13}}{C_1}}}{{^5{C_4}}}$
D
$ \frac{{^{13}{C_3}{ \times ^{13}}{C_1}}}{{^5{C_4}}}$
Solution
Number of ways of drawing $4$ cards from $52$ cards $=^{52} C_{4}$
In a deck of $52$ cards, there are $13$ diamonds and $13$ spades.
$\therefore$ Number of ways of drawing $3$ diamonds and one spade $=^{13} C_{3} \times^{13} C_{1}$
Thus, the probability of obtaining $3$ diamonds and one spade $ = \frac{{^{13}{C_3}{ \times ^{13}}{C_1}}}{{^5{C_4}}}$
Standard 11
Mathematics