{{sqrt 2 } over {sqrt {(2 + sqrt 3 )} - sqrt | vedclass

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Question

(b) ${{\sqrt 2 } \over {\sqrt {2 + \sqrt 3 } - \sqrt {2 - \sqrt 3 } }} = {{\sqrt 2 \,\left( {\sqrt {2 + \sqrt 3 } + \sqrt {2 - \sqrt 3 } } \right)} \o

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(b) ${{\sqrt 2 } \over {\sqrt {2 + \sqrt 3 } - \sqrt {2 - \sqrt 3 } }} = {{\sqrt 2 \,\left( {\sqrt {2 + \sqrt 3 } + \sqrt {2 - \sqrt 3 } } \right)} \over {(2 + \sqrt 3 ) - (2 - \sqrt 3 )}}$

$ = {{\sqrt {4 + 2\sqrt 3 } + \sqrt {4 - 2\sqrt 3 } } \over {2\sqrt 3 }} = {{(\sqrt 3 + 1)\, + \,(\sqrt 3 - 1)} \over {2\sqrt 3 }} = 1$.

${{\sqrt 2 } \over {\sqrt {(2 + \sqrt 3 )} - \sqrt {(2 - \sqrt 3 } )}} = $

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