sqrt {(3 + sqrt 5 )} - sqrt {(2 + sqrt 3 )} = | vedclass

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Question

(b) $\sqrt {(3 + \sqrt 5 )} - \sqrt {2 + \sqrt 3 } = \sqrt {{{6 + 2\sqrt 5 } \over 2}} - \sqrt {{{4 + 2\sqrt 3 } \over 2}} $

$ = {1 \over {\sqrt 2

Vedclass · Accepted Answer

$\sqrt {(5/2)} - \sqrt {(3/2)} $

Vedclass · Answer

(b) $\sqrt {(3 + \sqrt 5 )} - \sqrt {2 + \sqrt 3 } = \sqrt {{{6 + 2\sqrt 5 } \over 2}} - \sqrt {{{4 + 2\sqrt 3 } \over 2}} $

$ = {1 \over {\sqrt 2 }}\,[(1 + \sqrt 5 ) - (1 + \sqrt 3 )] = {1 \over {\sqrt 2 }}(\sqrt 5 - \sqrt 3 ) = \sqrt {{5 \over 2}} - \sqrt {{3 \over 2}} $.

$\sqrt {(3 + \sqrt 5 )} - \sqrt {(2 + \sqrt 3 )} = $

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