${C_0} - {C_1} + {C_2} - {C_3} + ..... + {( - 1)^n}{C_n}$ = . . .
${C_0} - {C_1} + {C_2} - {C_3} + ..... + {( - 1)^n}{C_n}$ = . . .
- A
${2^n}$
- B
${2^n} - 1$
- C
$0$
- D
${2^{n - 1}}$
Similar Questions
જો $^{20}{C_1} + \left( {{2^2}} \right){\,^{20}}{C_3} + \left( {{3^2}} \right){\,^{20}}{C_3} + \left( {{2^2}} \right) + ..... + \left( {{{20}^2}} \right){\,^{20}}{C_{20}} = A\left( {{2^\beta }} \right)$ થાય તો $(A, \beta )$ ની કિમત મેળવો.
જો $^{20}{C_1} + \left( {{2^2}} \right){\,^{20}}{C_3} + \left( {{3^2}} \right){\,^{20}}{C_3} + \left( {{2^2}} \right) + ..... + \left( {{{20}^2}} \right){\,^{20}}{C_{20}} = A\left( {{2^\beta }} \right)$ થાય તો $(A, \beta )$ ની કિમત મેળવો.
- [JEE MAIN 2019]
$(x - 1)$$\left( {x\, - \,\frac{1}{2}\,} \right)$$\left( {x\, - \,\frac{1}{{{2^2}}}\,} \right)$ .....$\left( {x\, - \,\frac{1}{{{2^{49}}}}\,} \right)$ ના વિસ્તરણમાં $x^{49}$ નો સહગુણક મેળવો
$(x - 1)$$\left( {x\, - \,\frac{1}{2}\,} \right)$$\left( {x\, - \,\frac{1}{{{2^2}}}\,} \right)$ .....$\left( {x\, - \,\frac{1}{{{2^{49}}}}\,} \right)$ ના વિસ્તરણમાં $x^{49}$ નો સહગુણક મેળવો
જો $r,k,p \in W,$ હોય તો $\sum\limits_{r + k + p = 10} {{}^{30}{C_r} \cdot {}^{20}{C_k} \cdot {}^{10}{C_p}} $ ની કિમત મેળવો
જો $r,k,p \in W,$ હોય તો $\sum\limits_{r + k + p = 10} {{}^{30}{C_r} \cdot {}^{20}{C_k} \cdot {}^{10}{C_p}} $ ની કિમત મેળવો
${C_1} + 2{C_2} + 3{C_3} + 4{C_4} + .... + n{C_n} = $
${C_1} + 2{C_2} + 3{C_3} + 4{C_4} + .... + n{C_n} = $
જો $\left({ }^{30} C _1\right)^2+2\left({ }^{30} C _2\right)^2+3\left({ }^{30} C _3\right)^2+\ldots \ldots+30\left({ }^{30} C _{30}\right)^2=$ $\frac{\alpha 60 !}{(30 !)^2}$ હોય,તો $\alpha=............$
જો $\left({ }^{30} C _1\right)^2+2\left({ }^{30} C _2\right)^2+3\left({ }^{30} C _3\right)^2+\ldots \ldots+30\left({ }^{30} C _{30}\right)^2=$ $\frac{\alpha 60 !}{(30 !)^2}$ હોય,તો $\alpha=............$
- [JEE MAIN 2023]