sin {163^o}cos {347^o} + sin {73^o}sin {167^o | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o}$

$ = \sin ({180^o} - {17^o})\cos ({360^o} - {13^o}) + \cos ({90^o} - {17^o})\sin ({180^o} -

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(b) $\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o}$

$ = \sin ({180^o} - {17^o})\cos ({360^o} - {13^o}) + \cos ({90^o} - {17^o})\sin ({180^o} - {13^o})$

$ = \sin {17^o}\cos {13^o} + \cos {17^o}\sin {13^o} $

$= \sin {30^o} = 1/2$.

$\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o} = $

Similar Questions

$2 \sin \left(\frac{\pi}{8}\right) \sin \left(\frac{2 \pi}{8}\right) \sin \left(\frac{3 \pi}{8}\right) \sin \left(\frac{5 \pi}{8}\right) \sin \left(\frac{6 \pi}{8}\right) \sin \left(\frac{7 \pi}{8}\right)$ का मान है -

$\tan 9^\circ - \tan 27^\circ - \tan 63^\circ + \tan 81^\circ = $

यदि $A = 133^\circ ,$ तब $\;2\cos \frac{A}{2} =$

$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $

यदि $(\sec A + \tan A)\,(\sec B + \tan B)\,(\sec C + \tan C)$$ = \,(\sec A - \tan A)\,(\sec B - \tan B)\,(\sec C - \tan C),$ तब प्रत्येक पक्ष बराबर है