$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $
$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $
- A
$0$
- B
$1/2$
- C
$1$
- D
$4\cos \alpha \cos \beta \cos \gamma $
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- [IIT 1979]
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