If alpha + beta + gamma = 2pi , then | vedclass

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Question

(a) We have $\alpha + \beta + \gamma = 2\pi $

$\Rightarrow \frac{\alpha }{2} + \frac{\beta }{2} + \frac{\gamma }{2} = \pi $ 

$ \Rightarrow

Vedclass · Accepted Answer

$	an \frac{\alpha }{2} + 	an \frac{\beta }{2} + 	an \frac{\gamma }{2} = 	an \frac{\alpha }{2}	an \frac{\beta }{2}	an \frac{\gamma }{2}$

Vedclass · Answer

(a) We have $\alpha + \beta + \gamma = 2\pi $

$\Rightarrow \frac{\alpha }{2} + \frac{\beta }{2} + \frac{\gamma }{2} = \pi $ 

$ \Rightarrow 	an \left( {\frac{\alpha }{2} + \frac{\beta }{2} + \frac{\gamma }{2}} ight) = 	an \pi = 0$ 

$ \Rightarrow 	an \frac{\alpha }{2} + 	an \frac{\beta }{2} + 	an \frac{\gamma }{2} - 	an \frac{\alpha }{2}	an \frac{\beta }{2}	an \frac{\gamma }{2} = 0$

$ \Rightarrow 	an \frac{\alpha }{2} + 	an \frac{\beta }{2} + 	an \frac{\gamma }{2}$

$= 	an \frac{\alpha }{2}	an \frac{\beta }{2}	an \frac{\gamma }{2}$.

If $\alpha + \beta + \gamma = 2\pi ,$ then

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