$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $

  • A

    $0$

  • B

    $1/2$

  • C

    $1$

  • D

    $4\cos \alpha \cos \beta \cos \gamma $

Similar Questions

यदि $\tan x = \frac{b}{a},$ तो $\sqrt {\frac{{a + b}}{{a - b}}} + \sqrt {\frac{{a - b}}{{a + b}}} = $

यदि $\frac{\sqrt{2} \sin \alpha}{\sqrt{1+\cos 2 \alpha}}=\frac{1}{7}$ तथा $\sqrt{\frac{1-\cos 2 \beta}{2}}=\frac{1}{\sqrt{10}}, \alpha$, $\beta \in\left(0, \frac{\pi}{2}\right)$, हैं, तो $\tan (\alpha+2 \beta)$ बराबर ........ है |

  • [JEE MAIN 2020]

$\cos 20^\circ \cos 40^\circ \cos 80^\circ = $

यदि $\cos x + \cos y + \cos \alpha = 0$ तथा $\sin x + \sin y + \sin \alpha = 0,$ तब $\cot \,\left( {\frac{{x + y}}{2}} \right) = $

यदि $A + B + C = {180^o},$ तब $(\cot B + \cot C)\,(\cot C + \cot A)$ $(\cot A + \cot B)$ का मान होगा