$\frac{{\sqrt {1 + \sin x} + \sqrt {1 - \sin x} }}{{\sqrt {1 + \sin x} - \sqrt {1 - \sin x} }} = $ (when $x$ lies in $II^{nd}$ quadrant)

  • A

    $\sin \frac{x}{2}$

  • B

    $\tan \frac{x}{2}$

  • C

    $\sec \frac{x}{2}$

  • D

    ${\rm{cosec}}\frac{x}{2}$

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