$2\sin A{\cos ^3}A - 2{\sin ^3}A\cos A = $
$2\sin A{\cos ^3}A - 2{\sin ^3}A\cos A = $
- A
$\sin 4A$
- B
$\frac{1}{2}\sin 4A$
- C
$\frac{1}{4}\sin 4A$
- D
None of these
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$2\cos x - \cos 3x - \cos 5x = $
$2\cos x - \cos 3x - \cos 5x = $
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8} = $
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8} = $
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$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $
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