$\frac{{\sec 8A - 1}}{{\sec 4A - 1}} = $
$\frac{{\sec 8A - 1}}{{\sec 4A - 1}} = $
- A
$\frac{{\tan 2A}}{{\tan 8A}}$
- B
$\frac{{\tan 8A}}{{\tan 2A}}$
- C
$\frac{{\cot 8A}}{{\cot 2A}}$
- D
None of these
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