sin 600^circ cos 330^circ + cos 120^circ sin | vedclass

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Question

(a) $\sin \,{600^o}\,\cos \,{330^o} + \cos \,{120^o}\,\sin \,{150^o}$

$ = - \sin \,{60^o}\,\cos \,{30^o} - \sin \,{30^o}\,\cos \,{60^o}$

$ = - \

Vedclass · Accepted Answer

$-1$

Vedclass · Answer

(a) $\sin \,{600^o}\,\cos \,{330^o} + \cos \,{120^o}\,\sin \,{150^o}$

$ = - \sin \,{60^o}\,\cos \,{30^o} - \sin \,{30^o}\,\cos \,{60^o}$

$ = - \left\{ {\sin \,({{60}^o} + {{30}^o})} \right\} = - 1$.

$\sin 600^\circ \cos 330^\circ + \cos 120^\circ \sin 150^\circ =....$

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