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3-1.Vectors
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$\frac{{{d^2}}}{{d{x^2}}}\,\,\left( {4{x^2}\,\, - \,\,3{x^2}\,\, + \;\,2x\,\, + \;\,1} \right)$ સદીશનું મૂલ્ય ..... થાય
A
$12x - 6$
B
$24x - 6$
C
$6x - 6$
D
$18x - 6$
Solution
$\frac{{{d^2}}}{{d{x^2}}}\,\,\,\left( {4{x^3}\,\, – \,\,3{x^2}\,\, + \;\,2x\,\, + \;\,1} \right)\,\, = \,\,\,\frac{d}{{dx}}\,\,\left( {12{x^2}\,\, – \,\,\,6x\,\, + \;\,2} \right)\,\, = \,\,24x\,\, – \,\,6$
Standard 11
Physics
